We get A squared is equal to h squared minus h squared over 4.

Pythagorean Theorem, you get x squared plus y squared is equal to r squared.

We get a squared over h squared plus o squared over h squared is equal to 1, right?

So we'll get c squared plus a squared minus b squared is equal to 2cx.

It's x squared plus y squared, so you get x squared plus y squared is equal to a to the fourth.

I'm gonna get myself squared around.

So the radius away from the center, that's just going to be r squared is just x squared plus y squared plus z squared.

It tells us right there. r squared is equal to x squared plus y squared. So you get x squared plus y squared is equal to 4y.

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So you get r squared is equal to what's a squared squared? Well, it's a to the fourth, right?

If multiply these, you get 7z squared.

Then from this right hand triangle, I get c minus x squared plus h squared is equal to b squared.

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Two divided by two you get one there, you get a two here divide by B, get a one that just has becomes an A and so you get 25 is equal to the numerator squared of A squared of B squared times itself it's just gonna be A squared plus B squared over 2A

So we get 2x squared is equal to 100. x squared is equal to 50.

So we get 6 squared is 36, plus B squared, is equal to 12 squared this 12 times 12 is 144.

So, you get (a) squared plus 2ab plus (b) squared is equal to 4 times 1 2 is 2ab plus c squared.

So you'd get a squared, plus 1 2 squared, which is 1 4, which is equal to 1 squared, which is 1.

So we get 3 times sine squared of x.

Fine way to get squared around, teaming with them.

let's multiply both sided by 2B we get 25B is equal to A squared plus B squared

Then if we divide both sides by 2c, we get c squared plus a squared minus b squared over 2c is equal to x.

Well, if we take this term and this term, we get those two terms are b squared sine squared of theta plus b squared cosine this should be squared there, right, because we squared it. b squared cosine squared of theta, and then we have plus c squared minus 2bc cosine theta.

So we get 3 Well cosine squared x. That's the same thing as cosine of x squared, right?

So we'll get twenty five sine squared of theta is equal to square three cosine squared of theta, Instead of writing cosine squared of theta,

Instead of x squared plus y squared plus z squared, I wrote r squared, just to kind of give you the intuition that this expression is just saying the square of the distance as we get away from the center of our room, or from the coordinate 0, 0, 0.

I just squared both sides and so we get twenty five sine squared theta is equal to three minus three sine squared theta and we can add three sine squared theta to both sides we get twenty eight sine squared theta is equal to three, or that the sine squared theta,home stretch,to three over twenty eight

Because you're taking x squared, you always get positive values.

And if I square them I get a b squared.

Otherwise, it would be weird to get a squared here.

So times c squared plus a squared minus b squared, squared.

Plus 5a squared b squared minus 2a squared b squared, right?

If I subtracted sine squared of a from both sides you could get cosine squared of a is equal to 1 minus sine squared of a.

And if you square meters per second, you're going to get meters squared per second squared divided by the acceleration of gravity, meters per second squared.

So let's say I have 2a squared b, minus 3ab squared, plus 5a squared b squared, minus 2a squared b squared, plus 4a squared b, minus 5b squared.

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